Posted by Zinhle on Monday, March 18, 2013 at 3:24pm.
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13sinx+5=0
sinx = -5/13
sinx is negative in QIII,QIV, but we want the QIII value.
so, cosx = -12/13
sin2x = 2sinx cosx = 2(-5/13)(-12/13) = 120/169
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