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March 5, 2015

March 5, 2015

Posted by **Zinhle** on Monday, March 18, 2013 at 3:24pm.

- ??? -
**Writeacher**, Monday, March 18, 2013 at 3:43pmIf you really want the help of an expert in this subject, you'll

**follow directions**and put the SUBJECT in the School Subject box.

- Trig -
**Steve**, Monday, March 18, 2013 at 3:53pm13sinx+5=0

sinx = -5/13

sinx is negative in QIII,QIV, but we want the QIII value.

so, cosx = -12/13

sin2x = 2sinx cosx = 2(-5/13)(-12/13) = 120/169

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