Posted by brittany on Monday, March 18, 2013 at 2:59pm.
metal loss of heat + water gain of heat = 0
[(mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for specific heat metal. Then look up in a specific heat table to identify the metal.
Related Questions
chemistry - a 225.0g sample of an unknown, silver, pure metal was heated to 95.5...
science - a 100.0 gram metal sample is heated to a temperature of 110 degrees ...
Chemistry - A 108g piece of unknown metal is heated to 100 degrees C in boiling ...
Chemistry - A 50g sample of metal was heated to 100 degrees Celsius and then ...
Chemistry - A 40.0g sample of an unknow, yellowish-brown, pure metal was heated ...
Chemistry - A 40.0g sample of an unknow, yellowish-brown, pure metal was heated ...
Chemistry - A 125-g piece of metal is heated to 288 degrees celsius and dropped ...
chemistry - a 23.8 g sample of unknown metal heated at 100 degrees c is placed ...
Chemistry - An unknown metal, heated to an unknown temperature until a liquid is...
chemistry - A metal sample weighing 45.0 g and at a temperature of 99.1 degrees ...
For Further Reading
