Posted by **Crystal** on Monday, March 18, 2013 at 12:46pm.

Precalc

(1+i)^3

and

the cube root of 8i

- Math -
**Steve**, Monday, March 18, 2013 at 1:32pm
(1+i) = (√2,pi/4)

so, (1+i)^3 = (2√2,3pi/4) = (-2+2i)

8i = (8,pi/2)

(8i)^(1/3) = (2,pi/6) = (√3+i)

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