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March 27, 2017

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Precalc
(1+i)^3
and
the cube root of 8i

  • Math - ,

    (1+i) = (√2,pi/4)
    so, (1+i)^3 = (2√2,3pi/4) = (-2+2i)

    8i = (8,pi/2)
    (8i)^(1/3) = (2,pi/6) = (√3+i)

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