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posted by Crystal on Monday, March 18, 2013 at 12:46pm.

Precalc (1+i)^3 and the cube root of 8i

(1+i) = (√2,pi/4) so, (1+i)^3 = (2√2,3pi/4) = (-2+2i) 8i = (8,pi/2) (8i)^(1/3) = (2,pi/6) = (√3+i)

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