Posted by **gandhish** on Monday, March 18, 2013 at 12:32pm.

find the coefficient of x^29 in the expansion (1+2x)^12 .(1+x)^18

- math -
**Steve**, Monday, March 18, 2013 at 1:38pm
(2x+1)^12

= (2x)^12 + 12(2x)^11 + ...

= 2^12 x^12 + 12*2^11 x^11 + ...

(x+1)^18 = x^18 + 18x^17 + 9*17 x^16 + ...

= 2^12 x^30 + (18*2^12 + 12)x^29 + ...

so, 18*2^12 + 12 = 73740

- math -
**Steve**, Monday, March 18, 2013 at 1:45pm
(2x+1)^12 = 2^12 x^12 + 12*2^11 x^11 + ...

(x+1)^18 = x^18 + 18x^17 + ...

multiply the two expansions to get

2^12 x^30 + (18*2^12 + 12*2^11) x^29 + ...

so, we have 18*2^12 + 12*2^11 = 98304

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