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April 2, 2015

April 2, 2015

Posted by **Christina** on Monday, March 18, 2013 at 9:03am.

The answer I got was .9536803695 is the correct?

- Stats. -
**PsyDAG**, Monday, March 18, 2013 at 12:13pmSEm = 16/√48 = 16/6.9282 = 2.3

Z = (score-mean)/SEm = (100-96)/2.3 = 1.7

Z = (score-mean)/SEm = (90-96)/2.3 = -2.6

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z scores.

.4554 + .4953 = .9507

Yep, .95 is close enough

- Stats. -
**Christina**, Monday, March 18, 2013 at 12:51pmThank you so much

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