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March 6, 2015

March 6, 2015

Posted by **Stranger** on Monday, March 18, 2013 at 5:16am.

1♡=1; n♡=((n−1)♡)⋅n+1

Find the largest n<1000 such that the last two digits of n♡ are zeroes.

Just to make it clear: unlike "n-factorial," "n-heart" is NOT an official mathematical terminology.

- Algebra -
**Steve**, Monday, March 18, 2013 at 10:50am919♡ = 19328918...75566100

but I haven't yet come up with a number-theoretic argument.

The values of n where n♡ ends in 00 are

19 107 119 207 219 307 319 407 419 507 519 607 619 707 719 807 819 907 919

It appears that there's a pattern there, no? More thought needed.

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