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October 1, 2014

October 1, 2014

Posted by **Jackie** on Monday, March 18, 2013 at 2:04am.

- college algebra -
**Steve**, Monday, March 18, 2013 at 4:32amIf you are confused by formulas, it indicates you don't really understand the concepts. Let's start from scratch.

You know the graph is a parabola, which has a vertex.

Since the coefficient of x^2 is positive, the vertex is at the minimum value of y.

So, left of the vertex y is decreasing, and on the right, it is increasing.

So, where is the vertex?

y = 2x^2 - 12x + 19

= 2(x^2-6x) + 19

= 2(x^2-6x+9) + 19 - 18

= 2(x-3)^2 + 1

So, the vertex is at (3,1)

y decreases for x < 3

y increases for x > 3

- college algebra -
**Jag**, Saturday, March 23, 2013 at 7:50pmVertex is -b/2a

ax^2+by+c=0

or

(x2-x1)/(y2-y1)

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