How many liters in volume are occupied by 250 liters of bromine at STP?
250 L, but if you meant moles then 250*(22.4L)= volume at STP.
Your question doesn't make that much sense.
Br2 is a liquid at room temperature. So I would say it occupied 250 L at STP.
To calculate the volume of 250 liters of bromine at STP, we need to consider Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.
At STP (Standard Temperature and Pressure), the conditions are defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere of pressure.
Since bromine is a liquid at STP, we need to convert it to its gaseous state to apply Avogadro's Law. For this conversion, we'll use the concept of molar volume, which is the volume occupied by one mole of any gas at STP.
The molar volume of a gas at STP is approximately 22.4 liters/mol.
To calculate the volume of bromine in liters at STP, we can use the following steps:
1. Convert the given 250 liters of bromine to moles.
- To do this, we need to know the molar mass of bromine. Bromine has an atomic mass of approximately 79.9 grams/mol. Therefore, its molar mass is 79.9 grams.
- Divide the given mass (in grams) by the molar mass of bromine to obtain moles.
250 liters * (1 mole / 22.4 liters) = 11.16 moles
2. Now we know that 250 liters of bromine at STP corresponds to 11.16 moles of bromine, using Avogadro's Law.
To answer the question, 250 liters of bromine at STP would occupy approximately 11.16 liters of volume.