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February 1, 2015

February 1, 2015

Posted by **Matthew** on Sunday, March 17, 2013 at 11:03pm.

What is the rate of depreciation? (1 mark)

What will the car be worth after 5 years? (1 mark)

To the nearest month, how long would it take to reduce the vehicle’s value to 10% of its original amount? (3 marks)

- math -
**Reiny**, Monday, March 18, 2013 at 12:09amyou probably meant

V = 25000 (.85)^y

a) replace y with 5

V = 25000(.85)^5

= ....

b) when is it worth 2500 ?

(.85)^y = .10

log both sides

log (.85^t) = log .10

t log .85 = log .10

t = log .10/log .85 = 14.168 years

or 14 years and 2 months

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