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Chemistry

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At 22 °C an excess amount of a generic metal hydroxide M(OH)2, is mixed with pure water. The resulting equilibrium solution has a pH of 10.49. What is the Ksp of the salt at 22 °C?

Is the ksp=1.38*10^-11?

  • Chemistry -

    M(OH)2---> M^+ + 2OH

    14-pH=pOH

    14-10.49=3.51


    pOH=-log[OH]


    10^(-3.51)=OH concentration

    OH concentration is twice as much as M from the reaction.


    Ksp=products/reactants=[OH Concentration]^2[OH concentration/2]


    I calculate 1.48 x 10^-11

  • Chemistry -

    I agree with 1.48E-11

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