There is a picture with stacked cubes that are each 2inches.
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++++ +=the pic i have of cubes=(+=2in cube)
Each side of a cube in the diagram measures 2 inches. What is the total surface area and volume of the solid?
I did A=s squared A=2 squared
A= 4inch squared
SA= 4(36)= 144inch squared
V=lw10
v=2(2)10 = 40 inch cubed
is this correct?
These are the numbers I got to plug into the formula
front and back of the tower=20
side=4 bottom=4 side#2=4 top=4
all together =36, this is how I came up with my numbers. Hopefully, I did it correctly. Thanks for checking this
To find the total surface area and volume of the solid, you need to consider all the faces of the stacked cubes.
First, let's calculate the total surface area (SA):
- Each side of a cube measures 2 inches, so the area of one face is 2 inches multiplied by 2 inches, which gives you 4 square inches.
- The solid consists of 36 cubes, so there are 36 faces in total.
- To calculate the total surface area, you multiply the area of one face by the number of faces: 4 square inches multiplied by 36 faces equals 144 square inches.
Therefore, the total surface area of the solid is 144 square inches.
Next, let's calculate the volume (V):
- The length, width, and height of each cube are all 2 inches.
- The solid consists of 36 cubes, so the length, width, and height of the solid are also 2 inches.
- To calculate the volume of the solid, you multiply the length, width, and height: 2 inches multiplied by 2 inches multiplied by 2 inches equals 8 cubic inches.
- Since there are 36 identical cubes, you multiply the volume of one cube by 36: 8 cubic inches multiplied by 36 equals 288 cubic inches.
Therefore, the volume of the solid is 288 cubic inches.
So, based on your calculations, your answer is incorrect. The correct values for the total surface area and volume are:
- The total surface area of the solid is 144 square inches.
- The volume of the solid is 288 cubic inches.
I hope this explanation helps you understand how to calculate the total surface area and volume of stacked cubes.