Posted by Luis on Sunday, March 17, 2013 at 5:11pm.
How do I find the exact value of sin (pi/24)?

trig  Steve, Sunday, March 17, 2013 at 5:24pm
sin π/6 = 1/2
cos π/6 = √3/2
sin(x/2) = √(1cosx) / 2
cos(x/2) = √(1+cosx) / 2
apply the halfangle formula twice to get
sin π/24 = 1/2 √(2√(2+√3))

trig  Luis, Sunday, March 17, 2013 at 5:36pm
I am not under standing could you show me ? to tell me ?

trig  Luis, Sunday, March 17, 2013 at 5:40pm
I applied the half angle formula for sin and I got the square root of 2 minus the square root of 3 divided by 2 . and for cos I got thesqurof 2 plus thesqr of3divided by 2 .

trig  Luis, Sunday, March 17, 2013 at 5:43pm
I really need help . I find this hard Steve .

trig  Luis, Sunday, March 17, 2013 at 5:51pm
Do I subtract ?

trig  Steve, Monday, March 18, 2013 at 9:50am
sin π/6 = 1/2
cos π/6 = √3/2
so,
cos π/12 = √(1+√3/2) / 2
sin π/24 = √(1cos π/12) / 2
= 1/2 √(1  (√(1+√3/2) / 2))
= 1/2√2 √(2  √(1+√3/2))
= 1/4 √(2√2  √(1+√3))
...
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