Posted by Luis on .
How do I find the exact value of sin (pi/24)?

trig 
Steve,
sin π/6 = 1/2
cos π/6 = √3/2
sin(x/2) = √(1cosx) / 2
cos(x/2) = √(1+cosx) / 2
apply the halfangle formula twice to get
sin π/24 = 1/2 √(2√(2+√3)) 
trig 
Luis,
I am not under standing could you show me ? to tell me ?

trig 
Luis,
I applied the half angle formula for sin and I got the square root of 2 minus the square root of 3 divided by 2 . and for cos I got thesqurof 2 plus thesqr of3divided by 2 .

trig 
Luis,
I really need help . I find this hard Steve .

trig 
Luis,
Do I subtract ?

trig 
Steve,
sin π/6 = 1/2
cos π/6 = √3/2
so,
cos π/12 = √(1+√3/2) / 2
sin π/24 = √(1cos π/12) / 2
= 1/2 √(1  (√(1+√3/2) / 2))
= 1/2√2 √(2  √(1+√3/2))
= 1/4 √(2√2  √(1+√3))
...