The coil of a generator has a radius of 0.12 m. When this coil is unwound, the wire from which it is made has a length of 5.8 m. The magnetic field of the generator is 0.21 T, and the coil rotates at an angular speed of 26 rad/s. What is the peak emf of this generator?
Answer in V
Physics - drwls, Sunday, March 17, 2013 at 2:54am
Use the information on wire length and radius to get the number of turns, N.
5.8 meters = 2*pi*R*N
N = 7.7 Let's call it 7 turns. The other 0.7 m might be used for connections.
Maximum Flux = Phi = N*B*A
= 0.067 Webers
Peak EMF = w*Phi= 1.7 volts
where w is the angular velocity of the coil.