Wednesday
October 22, 2014

Homework Help: chemisty

Posted by sreedevi on Saturday, March 16, 2013 at 11:32pm.

3.14M NaN3 (pKb=9.28) is titrated with .663M HClO4 until it reaches the equivalence point. How do you calculate the pOH at the equivalence point.

I tried and got something around 9 but its not correct i used a table but without liters given i have not idea where to go or what to do. Please help!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - Calculate the pH at the halfway point and at the equivalence point ...
Chemisty - In titrations of acids and bases, what is the difference between the ...
Chemistry - The phosphoric acid in a 100.00 mL sample of a cola drink was ...
Chemistry - A 40.00 mL sample of 0.1 M NH3 is titrated with 0.150 M HCl solution...
Chemistry - Calculate the pH at the halfway point and at the equivalence point ...
Chemistry - Calculate the pH at the halfway point and at the equivalence point ...
Chemistry - Calculate the pH at the halfway point and at the equivalence point ...
chemistry - Which of the following statements is true concerning the titration ...
AP Chemistry - Assume that 30.0 mL of a 0.10 M solution of a weak base B that ...
chemistry - A 30 mL sample of .165 M propanoic acid is titrated with .300M KOH. ...

Search
Members