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October 30, 2014

October 30, 2014

Posted by **Jenn** on Saturday, March 16, 2013 at 10:54pm.

a) the horizontal asymptote(s),

b) the vertical asymptote(s), if any, and

c) the oblique asymptote(s), if any.

F(x) = x^2-x-2/2x^2-x-2

- Given the following rational function -
**Steve**, Sunday, March 17, 2013 at 6:59ama long division shows that

F(x) = 1/2 - (x+2)/(2(2x^2-x-2))

so, as x gets large, F(x) -> 1/2

vertical asymptotes where 2x^2-x-2=0

no oblique asymptotes.

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