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March 5, 2015

March 5, 2015

Posted by **lisa** on Saturday, March 16, 2013 at 10:03pm.

[6,6.4],[6.4,6.8],[6.8,7.2],[7.2,7.6].

Suppose that f(6)=19, f'(6)=0, f'(6.4)=−0.5, f'(6.8)=−0.1, and f'(7.2)=−0.1. What is the approximate value of f(7.6)?

- calculus -
**bobpursley**, Saturday, March 16, 2013 at 10:18pmI bet it is (using the left side) is

first figure the values a the left side of each interval.

f(6)=given 19

f(6.4)=f(6)+.4*f'(6)=19

f(6.8)=f(6.4)+f'(6.4)*.4=19-.2= 18.8

f(7.2)=f(6.8)+f'(6.8)*.4=18.8-.04=18.76

f(7.6)=18.76-.4*.1=18.72

so check all those, it is easy to make an error when doing it on a keyboard.

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