Posted by **ES** on Saturday, March 16, 2013 at 10:02pm.

I asked this earlier today but did not get help. Can you please let me know if this question is done properly? Thank you

Camern is wrapping a present. She does not want any left over wrapping paper. How much wrapping paper does she need to buy. The length of the box is 15in,

the width is 3in and the height in 7 in.

I did it this way.

front and back(height)

SA=lw*2

SA=15(7)2

SA=210in squared

Sides( width)= SA=lw*2

SA=3(7)2= 42 in squared

Top and bottom(length

SA=15(3)2

SA=90in squared

Total surface area is SA=210=42=90=342in squared

SHe must buy 342 in squared of wrapping paper

Did I do all the steps correctly.

Thanks

- math -
**Ms. Sue**, Saturday, March 16, 2013 at 10:19pm
You're right. I got the same answer.

:-)

- math -
**bobpursley**, Saturday, March 16, 2013 at 10:21pm
Yes, however, I wonder how she wraps those pieces with no overlap. I think it is mosty not possible.

- math -
**ES**, Saturday, March 16, 2013 at 10:23pm
Thank you!!!

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