May 1, 2016

Homework Help: Maths A

Posted by Bella on Saturday, March 16, 2013 at 7:25pm.

Sue was sailing in the area shown on the chart on 3 March 2013. At 9:00 a.m., she sighted the antenna mast on Wellings Island on a bearing of 180T. Sue also took a sighting to the lighthouse on Abby Island and found it was at an angle of 098M.

(i) Sue sighted the antenna mast on a bearing of 180T. Determine the true bearing from the antenna mast to Sues boat.
(ii) Steve was at the lighthouse at 9:00 a.m. on that day. What was (i) the magnetic bearing and (ii) the true bearing from Steve to Sues boat?
(iii) Using the information from (i), draw and label a sighting line from the antenna mast. Using the information from (ii), draw and label a sighting line from the lighthouse. Hence find Sues position on the chart at 9:00 a.m. Mark this position using the appropriate navigation symbol and label it with the time.

Note: Use the centre of the base of the mast symbol and the centre of the star of the lighthouse symbol as reference points.

c. At 10:50 a.m. on 10 March 2013, a vessel was at 3030S 150E. From here, the vessel travelled on a course of 230M for 2 hours at an average speed of 10 knots. When this location was reached the vessel turned onto a heading that would enable it to reach the port at Nadia on Wellings Island.

(i) KP
Given that the variation in this area is 10E, what was the true bearing for the first leg of this journey? How far had the vessel travelled by 12:50 p.m.? In millimetres, what length on the chart represents this distance travelled?
(ii) KP
Draw the two legs of the vessels journey on the chart. Label each of the lines.

(iii) KP
State the location of the vessel at its position near Sunday Island (end of the vessels 1st leg).

(iv) MP Level 3
If the vessel had delayed changing course until the second leg could be at 90 to the first leg, how much earlier or later would the vessel have arrived at Nadia assuming that the vessel travelled at an average speed of 10 knots through the whole trip? Give your answer to the nearest minute

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