Camern is wrapping a present. She does not want any left over wrapping paper. How much wrapping paper does she need to buy. The length of the box is 15in,
the width is 3in and the height in 7 in.
I did it this way.
front and back(height)
SA=lw*2
SA=15(7)2
SA=210in squared
Sides( width)= SA=lw*2
SA=3(7)2= 42 in squared
Top and bottom(length
SA=15(3)2
SA=90in squared
Total surface areais SA=210=42=90=342in squared
He must buy 342 in squared of wrapping paper
Did I do all the steps correctly.
Thanks
As = 2(W*h + L*h + L*W)
As = 2(21 + 105 + 45) = 2(171)=342 in^2=
Surface area.
Yes, you did the steps correctly! To find the amount of wrapping paper needed, you calculated the surface area of each side of the box and added them together.
The front and back sides have a height of 7 inches and a width of 15 inches, so the surface area is SA = 15 * 7 * 2 = 210 square inches.
The sides have a height of 7 inches and a width of 3 inches, so the surface area is SA = 3 * 7 * 2 = 42 square inches.
The top and bottom sides have a length of 15 inches and a width of 3 inches, so the surface area is SA = 15 * 3 * 2 = 90 square inches.
By adding up the surface areas, you correctly determined that the total surface area is 210 + 42 + 90 = 342 square inches. Therefore, Cameron must buy 342 square inches of wrapping paper to ensure she doesn't have any leftover. Well done!