Homework Help: Chemistry

Posted by Lisa on Saturday, March 16, 2013 at 9:46am.

For calculating the concentration of a metal Ion in Equilibrium with a complex ion...how do I get the right hand side of this equation to equal 5.9 E -8?

x(0.98 + 2x)2
_____________ = 1.7 E 7
(0.010-x)

then,

x(0.98)2
________ = 5.9 E -8
0.010

I understand that you cancel out the 2x and - x, but I can't figure out how 5.9E -8 was obtained?

Chemistry - DrBob222, Saturday, March 16, 2013 at 2:07pm
From what you have I don't know either. Perhaps you can post the entire question and let us look at it.

Answer this Question

Related Questions

chemistry - Suppose that you wanted to be sure that a metal ion, any metal ion, ...
Chemistry terms - Match the terms with the correct definitions. 1. ligand 2. ...
Chemistry - Suppose that you wanted to be sure that a metal ion, any metal ion, ...
Chemistry - The following questions refer to the following system: 500 mL of 0....
DrBob222-Questions - Can you please check these for me. Thank you very much in ...
Chemistry - EQUILIBRIUM: To prepare the standard solution, a very large ...
Chemistry - What happens to the hydroxide ion concentration in aqueous solutions...
Chemistry - Hi there, I am doing some data calculations for my lab, but I'm ...
chemistry - Which if the following statements concerning complex ion Co(en)2Cl2...
Chemistry 102 - The Ksp for cerium iodate, Ce(IO3)3 is 3.2 e-10. What is the ...

For Further Reading

First Name:
School Subject:
Answer: