Friday

March 6, 2015

March 6, 2015

Posted by **Andrew** on Friday, March 15, 2013 at 10:04pm.

- math -
**Reiny**, Friday, March 15, 2013 at 10:41pmOn my screen your intended symbol did not show up correctly.

did you mean:

ln e = ln (√3/(x) ) - 4ln e ?

if so, then

5ln e = ln (√3/x)

ln e^5 = ln (√3/x)

anti-ln it

e^5 = √3/x

x = √3/e^5

Let me know if your equation was meant differently.

- math -
**Andrew**, Friday, March 15, 2013 at 10:53pmThank you for answering my question.But I really do not know what happend to the 4 in front of the equation?

- math -
**Reiny**, Friday, March 15, 2013 at 10:58pmahh, my error, I thought it was question #4

easy to fix

4 ln e = ln (√3/(x) ) - 4ln e

8ln e = ln (√3/x)

ln e^8 = ln (√3/x)

anti-ln it

e^8 = √3/x

x = √3/e^8

- math -
**Andrew**, Friday, March 15, 2013 at 11:03pmThank you for your help.

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