Posted by Paul on Friday, March 15, 2013 at 1:08pm.
∫xe^x^2+10 dx
the first term fits the pattern perfectly for differentiating terms of the type e^(u)
notice if I differentiate e^(x^2) , I get
2x e^(x^2), I am given half of that, so
∫xe^x^2+10 dx
= (1/2) e^(x^2) + 10x + C
for the second:
∫x-2/x-4 dx
using one step of a long division, we can show that
(x-2)/(x-4)
= 1 + 2/(x-4)
so ∫x-2/x-4 dx
= ∫1 + 2/x-4 dx
= x + 2ln(x-4) + C
Related Questions
Math - Evaluate the following indefinite integrals. ∫4e^6x dx &#...
Calculus - evaluating integrals - I'm really having trouble with this ...
Integral Help - 1.) ∫ (sin x) / (cos^2 x) dx 2.) ∫ (1) / (1+...
Help Evaluating Integrals - 1.) ∫ (2)/(x-4) dx 2.) ∫ sec^2x ...
Math integrals - What is the indefinite integral of ∫ [sin (π...
calculus (check my work please) - Not sure if it is right, I have check with the...
Integration? - Sorry, i have a load of questions on integration... thanks for ...
mathematics - ∫▒dx/(x√(2x^2+5x+1)) 2. ∫...
maths... - This is the entire question: A curve has the equation y=(x+2)&#...
Calculus - Find the integral by substitution ∫ [(16 x3)/(x4 + 5)] dx &...
For Further Reading
