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May 25, 2015

May 25, 2015

Posted by **Fadak** on Friday, March 15, 2013 at 11:37am.

- calculus -
**bobpursley**, Friday, March 15, 2013 at 1:23pmrate=changeinfunction/deltat as deltat >>0

rate=(8(t+h)(t+h+2))/h - 8(t(t+2)/h=

= 8/h * [(t^2+th+2t+ht+h^2+2h)-t^2+2t)

= 8/h * ( +2th+ +2h)

= 8 (2t+2)= 16(t+1)

and at t=a, then

ratechange=16(a+1)