Posted by KP on Friday, March 15, 2013 at 10:42am.
Do you mean 59 or 56?
Z = (score-mean)/SD
Z = (mean1 - mean2)/standard error (SE) of difference between means
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√n = 10/√25 = ?
If only one SD is provided, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
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