Monday

September 1, 2014

September 1, 2014

Posted by **KP** on Friday, March 15, 2013 at 10:42am.

- STATS -
**PsyDAG**, Friday, March 15, 2013 at 11:23amDo you mean 59 or 56?

Z = (score-mean)/SD

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n = 10/√25 = ?

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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