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January 29, 2015

January 29, 2015

Posted by **Devin** on Friday, March 15, 2013 at 6:22am.

- Calculus -
**Steve**, Friday, March 15, 2013 at 9:37amUsing shells:

v = ∫[0,2] 2πrh dx

where r = x and h = y = 2x^2 - x^3

v = 2π∫[0,2] 2x^3 - x^4 dx

piece of cake from here on

- Calculus -
**M**, Friday, March 15, 2013 at 10:22am16/5=21

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