An examination is normally distributed with a mean score of 77 and a deviation of 6. find the percent of individuals scoring as indicated below:
less than 65
between 77 and 65
Math computations - PsyDAG, Friday, March 15, 2013 at 11:28am
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores.