posted by Anonymous on .
During takeoff, an airplane climbs with a speed of 140 m/s at an angle of 42 degrees above the horizontal. The speed and direction of the airplane constitute a vector quantity known as the velocity. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)
horizontal component of the plane's velocity = 140 cos42 m/s