Answer the questions about the following functions.

f(x) = 14^2/x^4 + 49

(a) Is the point (-sqrt 7,1) on the graph of f?
(b) If x=1, what is f(x)? What point is on the graph of f?
(c) If f(x)=1, what is x? what point(s) are on graph of f?
(d)What is the domain of f?
(e) list the x-intercepts if any
(f) list the y-intercepts if any

Fix the typo

(d) the domain is all real numbers, since x^2+49 is never zero

The rest should be easy. Come back if you get stuck, and show how far you got.

To answer the questions about the function f(x) = 14^2/x^4 + 49, we can follow these steps:

(a) To determine if the point (-√7, 1) is on the graph of f, substitute x = -√7 into the function and check if it evaluates to y = 1. So, calculate f(-√7) and check if it equals 1.

(b) To find f(x) when x = 1, substitute x = 1 into the function f(x) = 14^2/x^4 + 49. This will give you the value of f(x) when x = 1. Additionally, you can find the corresponding point on the graph by representing it as (1, f(1)).

(c) To find the value(s) of x when f(x) = 1, you need to set f(x) equal to 1 and solve for x. This will give you the x-coordinate(s) of the point(s) on the graph where f(x) equals 1.

(d) The domain of f is the set of all possible values that x can take. In this case, the only restriction is that x should not be zero since division by zero is undefined.

(e) x-intercepts are the points on the graph where the function intersects the x-axis. To find x-intercepts, you need to set y = 0 and solve the equation 14^2/x^4 + 49 = 0 for x. If there are any valid solutions, these x-values correspond to the x-intercepts.

(f) y-intercepts are the points on the graph where the function intersects the y-axis. To find y-intercepts, you set x = 0 in the function f(x) = 14^2/x^4 + 49 and evaluate it. If the result is a valid number, that corresponds to the y-intercept(s).

By following these steps, you can find the answers to the questions about the given function f(x) = 14^2/x^4 + 49.