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April 16, 2014

April 16, 2014

Posted by **Nathan** on Thursday, March 14, 2013 at 9:53pm.

thanks

- Math -
**Steve**, Friday, March 15, 2013 at 9:48amn^2-7n+10 = (n-2)(n-5)

n^2-8n+15 = (n-3)(n-5)

LCD = (n-2)(n-3)(n-5), so we have

[3n(n-3) - 2n(n-2)] / ((n-2)(n-3)(n-5))

= (3n^2-9n-2n^2+4n) / (...)

= (n^2-5n) / (...)

= n(n-5) / (n-2)(n-3)(n-5)

= n / (n-2)(n-3)

= 3/(n-3) - 2/(n-2)

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