Posted by Mikayla on Thursday, March 14, 2013 at 8:54pm.
First factor the denominators.
3n/(n^2 -7n + 10) - 2n/(n^2-8n+15)
= 3n/[(n-5)(n-2)] -2n/[(n-5)(n-3)]
= [n/(n-5)] *{[3/(n-2)]-[2/(n-3)]}
= [n/(n-5)] *{[3(n-3)-2(n-2)/(n-2)(n-3)]}
= [n/(n-5)]*(n+5)/[(n-2)(n-3)]
This does not seem to be getting any simpler.
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