Sunday

February 1, 2015

February 1, 2015

Posted by **Mikayla** on Thursday, March 14, 2013 at 8:54pm.

- algebra 2 -
**drwls**, Friday, March 15, 2013 at 6:54amFirst factor the denominators.

3n/(n^2 -7n + 10) - 2n/(n^2-8n+15)

= 3n/[(n-5)(n-2)] -2n/[(n-5)(n-3)]

= [n/(n-5)] *{[3/(n-2)]-[2/(n-3)]}

= [n/(n-5)] *{[3(n-3)-2(n-2)/(n-2)(n-3)]}

= [n/(n-5)]*(n+5)/[(n-2)(n-3)]

This does not seem to be getting any simpler.

**Answer this Question**

**Related Questions**

Algebra - I am getting ready to start an Algebra class for the first time and I ...

SHAY - THE MATH QUESTION IS IT ALGEBRA , PRE ALGEBRA' OR GEOMETRY? Quadriatic ...

Algebra 1A - How is algebra a useful tool? what concepts investigated in algebra...

Algebra I - So- im trying to help my little brother out with his Algebra- but ...

Algebra-still need some help - Homework Help Forum: Algebra Posted by Jena on ...

algebra 1 - at a certain high school,350 students are taking algebra. the ratio ...

algebra - Is there a site or someone who can help me, im not getting the basic ...

7th grade - There are at least 5 more than twice as many students taking algebra...

algebra 2 - Posted by hellogoodbie on Saturday, January 16, 2010 at 3:24pm. ...

Algebra II - ok now this is an algebra 2 problem... I have goten far down to ...