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March 27, 2015

March 27, 2015

Posted by **Kim** on Thursday, March 14, 2013 at 8:09pm.

Scores: 172,122,189,106,196,195,151,155,162,195,231,204,232,213,209

- statistics -
**PsyDAG**, Friday, March 15, 2013 at 12:33pmHo: mean = 120

Ha: mean > 120

Find the mean first = sum of scores/number of scores

Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

Standard deviation = square root of variance

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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