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March 1, 2015

March 1, 2015

Posted by **John Miller** on Thursday, March 14, 2013 at 7:50pm.

- physics -
**bobpursley**, Thursday, March 14, 2013 at 9:43pmhf=hi+vi'*t+1/2 g t^2

where vi' is the vertical component of speed initially (Vsin45)

In the horizontal

d=VCos45*t

now t is the same in each equation, form the second, t=9.3*1.414/V; put that in the first equation for t..

3.05=1.85+V*.707*(9.3*1.414/V)+4.9(9.3*1.414/V)^2

multiply thru both sides by V^2, then you have a quadratic, solve using the qudaratic equation.

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