Posted by **John Miller** on Thursday, March 14, 2013 at 7:50pm.

A 1.85 m tall basketball player attempts a goal 9.3 m from a basket (3.05 m high). If he shoots the ball at a 45° angle, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard?

- physics -
**bobpursley**, Thursday, March 14, 2013 at 9:43pm
hf=hi+vi'*t+1/2 g t^2

where vi' is the vertical component of speed initially (Vsin45)

In the horizontal

d=VCos45*t

now t is the same in each equation, form the second, t=9.3*1.414/V; put that in the first equation for t..

3.05=1.85+V*.707*(9.3*1.414/V)+4.9(9.3*1.414/V)^2

multiply through both sides by V^2, then you have a quadratic, solve using the qudaratic equation.

## Answer This Question

## Related Questions

- physics - A 1.8 tall basketball player attempts a goal 11 from the basket that ...
- Physics - A 2.12 m tall basketball player wants to sink the ball into a basket ...
- PHYSICS - A 2.00 METER TALL BASKETBALL PLAYER ATTEMPTS A GOAL 10.00 METERS FROM ...
- physics - a 2.00 m tall basketball player is standing on the floor 10 m from ...
- physical - A basketball player who is 2.0m tall is standing on the floor 10.0m ...
- phy 231 - An h1 = 2.10 m tall basketball player wants to make a basket from a ...
- physics - A basketball player is standing on the floor 10.0 m from the basket as...
- physics - A basketball player is standing on the floor 10.0 m from the basket as...
- physics - A basketball player shoots the ball from a height of 2.22 m above the ...
- Physics - A basketball player 2.08 m tall wants to make a basket from a distance...

More Related Questions