How many valance electrons are there in [(C2H5)4N]+ ?

56

To determine the number of valence electrons in [(C2H5)4N]+, we need to consider the valence electrons contributed by each atom in the molecule.

First, let's break down the molecule into its constituent atoms:

C2H5 - represents two carbon (C) atoms and five hydrogen (H) atoms.
N - represents one nitrogen (N) atom.

Now, let's determine the number of valence electrons contributed by each atom:

Carbon (C) has 4 valence electrons.
Hydrogen (H) has 1 valence electron.
Nitrogen (N) has 5 valence electrons.

Since we have two carbon (C) atoms in the molecule, they contribute a total of 2 x 4 = 8 valence electrons.
The five hydrogen (H) atoms contribute a total of 5 x 1 = 5 valence electrons.
The nitrogen (N) atom contributes 5 valence electrons.

Thus, the total number of valence electrons in [(C2H5)4N]+ is 8 + 5 + 5 = 18 valence electrons.

To determine the number of valence electrons in [(C2H5)4N]+, we need to consider the valence electrons from each element in the molecule.

Let's break down the molecule [(C2H5)4N]+:

- The symbol "N" represents nitrogen, which is in Group 15 of the periodic table. Nitrogen has 5 valence electrons.

- The symbol "C" represents carbon. Each carbon atom in the molecule is part of an ethyl group (C2H5), which consists of two carbon atoms and five hydrogen atoms. Each carbon atom in the ethyl group has 4 valence electrons, and since we have four ethyl groups, the total number of valence electrons from carbon is 4 * 2 * 4 = 32.

- The symbol "H" represents hydrogen. There are 20 hydrogen atoms in the molecule (5 hydrogen atoms in each ethyl group), and each hydrogen atom brings 1 valence electron. So, the total number of valence electrons from hydrogen is 20 * 1 = 20.

Now, let's add up the valence electrons from each element:

Nitrogen (N): 5 valence electrons
Carbon (C): 32 valence electrons
Hydrogen (H): 20 valence electrons

Total valence electrons = 5 + 32 + 20 = 57

Therefore, there are 57 valence electrons in the molecule [(C2H5)4N]+.