What is the C-C-H bond angle in the molecule H2CCO?
abuseifabed087
To determine the C-C-H bond angle in the molecule H2CCO, we need to first draw the Lewis structure of the molecule.
The Lewis structure of H2CCO is as follows:
H - C = C - O
Next, let's label the atoms and bonds:
H
|
H - C = C - O
Now, we'll identify the bond angles by looking at the arrangement of atoms. The carbon atom in the center (C) has two different groups bonded to it: one hydrogen (H) atom and one carbon (C) atom. This molecule has a linear shape, and the bond angle between the two hydrogens and the central carbon atom is 180 degrees.
Therefore, the C-C-H bond angle in H2CCO is 180 degrees.
To determine the C-C-H bond angle in the molecule H2CCO, we need to consider the molecular geometry.
The Lewis structure of H2CCO shows that there are two carbon atoms connected by a double bond. Each carbon atom has two hydrogen atoms attached, and one carbon atom is also bonded to an oxygen atom. So the molecular formula can be written as H2C=C=O.
To find the bond angle, we need to examine the electronic arrangement of the atoms. In this case, the carbon atoms are sp2 hybridized, meaning that they have a trigonal planar electron arrangement.
With a double bond between the two carbon atoms, there are two electron domains around each carbon atom: one sigma bond and one pi bond. The hydrogen atoms are connected to each carbon atom, forming sigma bonds.
In a trigonal planar electronic arrangement, the bond angle between the adjacent atoms is expected to be approximately 120 degrees. Therefore, the C-C-H bond angle in H2CCO is approximately 120 degrees.
https://www.google.com/search?q=H2CCO&hl=en&client=firefox-a&hs=oUK&rls=org.mozilla:en-US:official&tbm=isch&tbo=u&source=univ&sa=X&ei=93NCUZTNDLDo2gXryIGACQ&ved=0CD4QsAQ&biw=853&bih=504
That looks like a trigonal planar angle of 60 degrees to me.