The amount of energy needed to heat 2.00 g mercury from 50.0°C to 85.0°C is 9.87 J. The specific heat capacity of this sample of mercury is

q = mass Hg x specific heat Hg x delta T

i got s= .14 JULESGRAMDEGREECELCIUS

If your prof is picky about the number of significant figures you might not get full credit for this. You have three s.f. in 9.87, 2.00, 35.0 and 85.0 so you are allowed 3 in the answer. Your answer contains only two. I obtained 0.141 J/g*C and notice the units are J/g*C and not JgC

To find the specific heat capacity of the sample of mercury, we can use the equation:

Q = mcΔT,

where Q is the amount of energy transferred, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature.

Given:
- mass of the sample (m) = 2.00 g
- initial temperature (T1) = 50.0°C
- final temperature (T2) = 85.0°C
- amount of energy transferred (Q) = 9.87 J

We need to rearrange the equation to solve for the specific heat capacity (c). Rearranging the equation, we have:

c = Q / (m * ΔT)

Substituting the given values, we get:

c = 9.87 J / (2.00 g * (85.0°C - 50.0°C))

Now, calculate the difference in temperature:

ΔT = T2 - T1 = 85.0°C - 50.0°C = 35.0°C

Substitute this value into the equation:

c = 9.87 J / (2.00 g * 35.0°C)

Calculating further, we find:

c = 9.87 J / (70 g*°C)

Finally, divide the energy by the mass and temperature to find the specific heat capacity:

c = 0.141 g*°C/J