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Posted by on Thursday, March 14, 2013 at 2:28pm.

calculate the mass and prepare 200ml 0.1M, 250 ml 0.2 N, 100 ml 3% of NaCl, Na2Co3 solution

  • NOT english - , Thursday, March 14, 2013 at 2:37pm

    .

  • Chemistry - , Thursday, March 14, 2013 at 2:44pm

    You will have to find the molar mass here..

    200 ml * 0.1 mol/ L * 1 L/ 1000 mL= 0.02M

    250 ml* 0.2M/ L * 1L/ 1000 mL= 0.05M N

    I somehow feel this problem is incomplete or either I am unable to understand the chemical compound name. Is there anymore to it?

  • english - , Thursday, March 14, 2013 at 3:20pm

    You have six problems here. Three are for NaCl and three for Na2CO3.

    For NaCl:
    200 mL of 0.1M:
    How many mols do you want? That's M x L = 0.1M x 0.200L = 0.02 mols.
    How many grams is that.
    mols = grams/molar mass. You know molar mass and mols; solve for grams.

    250 mL of 0.2 N. How many equivalents do you want? That's N x L = 0.05 equiv.
    How many grams is that?
    #equivalents = grams/equilvalent weight. You know # equivalents and equivalent weight; solve or grams.

    100 mL 3% NaCl (I assume that is % w/w.)
    3g NaCl/100 g solution.

    The Na2CO3 is done the same way.

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