A ball dropped from a height of 10m loses 40% of its energy after impact on ground. How much height will it gain after one impact?
6 meters. Why?
Even I need the answer to this question.
6m
To determine the height the ball will gain after one impact, we need to calculate the energy that is retained after the impact.
The ball loses 40% of its energy, which means it retains 60% of its energy after impact.
First, let's find out how much energy the ball has before impact. The potential energy of an object at a certain height can be calculated using the formula:
Potential energy = mass x gravity x height
Let's assume the mass of the ball is 1 kg, and the acceleration due to gravity is approximately 9.8 m/s^2.
Potential energy before impact = 1 kg x 9.8 m/s^2 x 10 m = 98 joules
Now, let's calculate the energy retained after impact.
Energy retained after impact = 60% of potential energy before impact
= 0.6 x 98 joules
= 58.8 joules
Finally, we need to calculate the height gained using the retained energy. The potential energy formula can be rearranged to solve for height:
Potential energy = mass x gravity x height
Rearranging, we get:
Height = Potential energy / (mass x gravity)
Height gained after one impact = 58.8 joules / (1 kg x 9.8 m/s^2)
= 6 meters
Therefore, the ball will gain a height of 6 meters after one impact.