Thursday
April 24, 2014

Homework Help: Derivatives

Posted by Mark on Thursday, March 14, 2013 at 11:28am.

what is derivative of sin^2 (3x-1)^2 ?

dy/dx (sin^2 (x))= 2 sin x cos x
dy/dx (3x-1)^2= 6(3x-1)

chain rule?
= 2 sin ((3x-1)^2) cos ((3x-1)^2) * 6(3x-1)

Please help. Thank you

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