Posted by Mark on .
what is derivative of sin^2 (3x1)^2 ?
dy/dx (sin^2 (x))= 2 sin x cos x
dy/dx (3x1)^2= 6(3x1)
chain rule?
= 2 sin ((3x1)^2) cos ((3x1)^2) * 6(3x1)
Please help. Thank you

Derivatives 
Mark,
I'm not sure if this is correct. Can someone clarify thanks.

Derivatives 
Steve,
you are correct
Or, you could go on and say
sin (2(3x1)^2) * 6(3x1) 
Derivatives 
Mark,
I got 12 sin (3x1)^2 cos (3x1)^2 * (3x1) as my final answer. Is this in the correct simplified form ?

Derivatives 
Steve,
it is ok, but you can use
2sinu cosu = sin(2u)
to make it what I had:
6(3x1) sin(2(3x1)^2)
If you want to retain your original argument of sin and cos, then leave it as you had it. 
Derivatives 
Mark,
I have taken that into consideration; thank you!