Posted by **Anonymous** on Thursday, March 14, 2013 at 9:12am.

The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 50 amps when the resistances is 20 ohms. What is the current when the resistance is 60 ohms?

- algebra -
**Steve**, Thursday, March 14, 2013 at 12:48pm
I = k/R

50 = k/20, so k = 1000, making

I = 1000/R

I(60) = 1000/60 = 16.67

- algebra -
**Anonymous**, Thursday, September 19, 2013 at 11:12am
if y varies directly as x and y = 9 when x =2 find when x =10

- algebra -
**Henry**, Wednesday, December 23, 2015 at 8:47pm
E = I*R = 50 * 20 = 1000 Volts = Supply

voltage.

I = E/R = 1000/60 = 16.67 Amps.

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