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Posted by Anonymous on Thursday, March 14, 2013 at 9:12am.

The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 50 amps when the resistances is 20 ohms. What is the current when the resistance is 60 ohms?

I = k/R 50 = k/20, so k = 1000, making I = 1000/R I(60) = 1000/60 = 16.67

if y varies directly as x and y = 9 when x =2 find when x =10

E = I*R = 50 * 20 = 1000 Volts = Supply voltage. I = E/R = 1000/60 = 16.67 Amps.

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