posted by Anonymous .
Assume the proton is at rest initially.
The charge on the proton is 1.602×10−19 C
and its mass is 1.67 × 10−27 kg.
If the magnetic ﬁeld is 2.85 T and the potential diﬀerence is 2.29 MV, ﬁnd the magnitude
of the force on the proton after the proton
passes through the potential diﬀerence.
Answer in units of N
012 (part 3 of 3) 10.0 points
The proton will subsequently move in a circle.
How many revolutions will the proton perform per second?
Answer in units of Hz