Indicate the concentration of each ion or molecule present in a mixture of 45.5 mL of 0.274 M NaCl and 65.5 mL of 0.0246 M (NH4)2CO3. Assume that the volumes are additive.
[Cl-]
[NH4+]
[CO32-]
mols Na = mols Cl = M x L = ?
M Na = M Cl = mols/total volume which is 45.5 mL + 65.5 mL = ? mL converted to L.
Do the (NH4)2CO3 the same way BUT note that the ratio is not 1:1 anymore.