Math (algerba 1)
posted by Katea on .
(4 X 10 to the 5th power) to the 2nd power.
How would I solve this?

Law of exponents says that you can distibute your power to when multiplying so you would have
4^2 x 10^10
I multiplied the two powers..
4^*1*2) x 10^(5*2)
16 x 10^10
I don't know if your teacher wants you to write this in a different form or not.
If could be 1.6 x 10^9