Posted by **steph** on Wednesday, March 13, 2013 at 7:15pm.

The length of a rectangle is 5cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle. So confused on how to do this problem please help me thanks.

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**Dr. Jane**, Wednesday, March 13, 2013 at 7:23pm
Perimeter = L + L + W + W

or P = 2L + 2W

L = 5+ 2w

P = 2(5+2W) + 2W

I replaces the L in the original formula with the 5 + 2w because that equals L according to the problem.

34 = 10 + 4W + 2W

Just solve for W.

And then you can find L.

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**steph**, Wednesday, March 13, 2013 at 7:27pm
Thanks

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**Dr. Jane**, Wednesday, March 13, 2013 at 7:29pm
You are welcome.

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**randy**, Tuesday, October 14, 2014 at 7:26pm
the length of marshalls rectangular poster is 2 times its width .if the perimeter is 24 inches what is the area of the poster?

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