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February 1, 2015

February 1, 2015

Posted by **John** on Tuesday, March 12, 2013 at 10:18pm.

- Physics -
**Elena**, Wednesday, March 13, 2013 at 7:19amh= vₒ²•sin²α/2•g =

=L•g•sin²α/2•g•sin2α=

= L•sinα/4•cos α=

=L•tanα/4

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