Posted by Kit on Tuesday, March 12, 2013 at 10:03pm.
A man is standing on a cliff and throws a ball outward 50m/s at an angle of 53 degrees. It hits the base of the cliff in 10 seconds.
Find:
a) The height of the cliff
b) the angle at which the ball goes into the sea
c) if the ball will hit a boat 150m out to sea.
h(t) = h - g/2to^2
After you drop the ball from a height of 20 feet and it hits the ground, it would reach a height of 15 ft
(just multiply your h by 3/4 each time to get the heights from each time it bounces...
20 * (3/4) = 15ft
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