Posted by **Anonymous** on Tuesday, March 12, 2013 at 6:07pm.

ABCD is a trapezoid with AB parallel to DC. If AB=25, BC=24, CD=50 and AD=7, what is the area of ABCD?

- geometry -
**Reiny**, Tuesday, March 12, 2013 at 7:39pm
We are going to need some sort of angle.

draw BE || AD, then ABED is a parallelogram and BE = 7

In triangle BCE,

BC = 24

BE = 7

CE = 50-25 = 25

by the cosine law:

7^2 = 24^2 + 25^2 - 2(24)(25)cosC

cosC = 1152/1200

angle C = 16.26... ---- I stored the entire number

we can now find the height:

sin 16.26... = height/24

height = 24sin16.26.. = 6.72 --- that came out exact

area = (1/2)(25+50)(6.72) = 252 square units

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