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November 24, 2014

November 24, 2014

Posted by **Jacob** on Tuesday, March 12, 2013 at 4:39pm.

Height:

Length:

Width:

- Applied Calculus -
**Steve**, Tuesday, March 12, 2013 at 4:54pmif side is x,

height is 112/x^2

area

a = x^2 + 4xh

= x^2 + 4x(112/x^2)

= x^2 + 28/x

da/dx = 2x - 28/x^2

da/dx=0 when x^3 = 14

and so on

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