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March 29, 2015

March 29, 2015

Posted by **rani** on Tuesday, March 12, 2013 at 1:19pm.

- physics -
**Elena**, Tuesday, March 12, 2013 at 4:57pmRate of cooling

R= ΔT₁/t₁=(80-50)/5=6 degr/min

t₂= ΔT₂/R=(60-30)/6=30/6=5 min

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