algebra...
posted by please...help...Ms.Sue.... on .
In a school, there are 4 more students in Class A than in Class B, and 4 more students in Class B than in Class C. As a reward for good behavior, a teacher decides to give out some sweets. Every student in class C got 5 more sweets than every student in Class B, and every student in Class B got 3 more sweets than every student in Class A. As it turns out, Class A got 10 more sweets than Class B, and Class B got 14 more sweets than Class C. How many sweets were given out in all?

668

A = number of students in class A
B = number of students in class B
C = number of students in class C
SA = number of sweets given to each student in class A.
SB = number of sweets given to each student in class B.
SC = number of sweets given to each student in class C.
A =B+4
B =C +4
SC = SB +5
SB = SA +3
AxSA = BxSB +10
BxSB = CxSC +14
A=18
B=14
C=10
SA=13
SB=16
SC=21
13+ 14x16+ 10x21 = 668