Posted by anoynomous on Tuesday, March 12, 2013 at 11:51am.
A box contains 5 red balls and 6 black balls. in how many ways can 6 balls be selected so that there are at least two balls of each color?

mathsprobabilty  Milan, Tuesday, August 23, 2016 at 8:24am
i) 2 red,4 black => C(5,2)*C(6,4) =150
ii)3 red,3 black => C(5,3)*C(6,3) =200
iii)4red,2 black => C(5,4)*C(6,2) =75
Therefore total number of ways =
150+200+75 = 425 ways
Hope this helps! Cheers! :)
Answer This Question
Related Questions
 mathsprobabilty(urgently needed)  A box contains 5 red balls and 6 black balls...
 maths  a box contains 5 red balls and 6 black balls in how many ways can 6 ...
 Math  A box containing 20 yellow balls, 9 red balls and 6 blue balls. If the ...
 Math  my problem is: From the box containing 5 red balls, 7 blue balls, 10 ...
 Math  my problem is: From the box containing 5 red balls, 7 blue balls, 10 ...
 d  given piles of identical red, blue and green balls where each pile contains ...
 Probability again  A box contains 6 red balls, 4 blue balls, and 2 green balls...
 Math  A bag contains three black balls, four white balls and five red balls. ...
 statistics  A box contains 3 white and 5 black balls. Four balls are drawn at ...
 Math  A bag contains 33 balls: 10 blue, 11 red, and 12 green. If a person will ...
More Related Questions