Posted by **anoynomous** on Tuesday, March 12, 2013 at 11:51am.

A box contains 5 red balls and 6 black balls. in how many ways can 6 balls be selected so that there are at least two balls of each color?

- maths-probabilty -
**Milan**, Tuesday, August 23, 2016 at 8:24am
i) 2 red,4 black => C(5,2)*C(6,4) =150

ii)3 red,3 black => C(5,3)*C(6,3) =200

iii)4red,2 black => C(5,4)*C(6,2) =75

Therefore total number of ways =

150+200+75 = 425 ways

Hope this helps! Cheers! :)

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